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SSC JE ME Previous Paper 1 (Held on: 25 Sep 2019 Evening)

- 0.625 m
- 1 m
- 23 cm
- 0.5 m

Option 4 : 0.5 m

Let's discuss the concepts related to Buoyancy and Floatation and Archimedes Principle. Explore more from Fluid Mechanics here. Learn now!

__Concept:__

Buoyancy Principle:

Buoyant Force (F) = Weight of displaced volume

Buoyant Force = Weight of displaced volume = (A × h × ρ _{w} × g) N

A = Base area of a cube, h = Depth of cube immersed in the seawater

**Floating principle, **

Buoyant force (F) = Weight of cube (W)

__Calculation:__

Weight of the cube (W) = Density × Volume × g = 500 × 1^{3} = (500 × g) N ...(1)

Buoyant Force (F) = (A × h × ρ_{w} × g) N = (1^{2} × h × 1000 × g) = (1000 × g × h) N ...(2)

Buoyant force (F) = Weight of cube (W)

From equation 1 and 2,

500 × g = 1000 × g × h

h = 0.5 m
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ST 1: General Knowledge

6215

20 Questions
20 Marks
20 Mins

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